xy

[gmatnmein2010]

If xy ≠ 0, is x > y?

(1) 4x = 3y

(2) |y - x| = x - y

[ajith]

If xy ≠ 0, is x > y?

(1) 4x = 3y

(2) |y - x| = x - y

1) is not sufficient (when x is -ve x>y and when x is positive x<y)


2) |y - x| = x - y => x-y is positive x>y
Sufficient

[thephoenix]

If xy ≠ 0, is x > y?

(1) 4x = 3y

(2) |y - x| = x - y

s1) not suff

for +ve x and +ve eqn of s1)------->x<y &
for -ve value of x and y------>x>y

s2)This means that equation |y-x|=x-y holds true when x-y>=0

bcoz ly-xl is a +ve entity

so x>=y not suff

(1)+(2) From (1) we got that x#y and from (2) x>=y , hence x>y. Sufficient.

IMO C

[bhumika.k.shah]

1.)4x = 3y

If x = 3 and y = 4
then we get an answer NO for is x>y

If x=-3 and y = -4
then we get an answer YES for is x >y

hence statement 1 is sufficient.

2.)|y - x| = x - y
only when x is greater than y is this possible.

Hence B

[harsh.champ]

1.)4x = 3y

If x = 3 and y = 4
then we get an answer NO for is x>y

If x=-3 and y = -4
then we get an answer YES for is x >y

hence statement 1 is sufficient.

2.)|y - x| = x - y
only when x is greater than y is this possible.

Hence B

Hey bhumika,
I think you missed the case when (x-y) = 0
In that case also,|y - x| will be equal to x - y as |0| = 0.
Hence,x can be => y but we cannot surely say if it is not equal.
Hence,St. B would be insufficient.

I would go with C over here.

[bhumika.k.shah]

whats the OA ?

if thts the case , then whats the purpose of giving xy is not equal to 0 in the question ?

[shashank.ism]

If xy ≠ 0, is x > y?

(1) 4x = 3y

(2) |y - x| = x - y

St.1 : 4x=3y --> x= 3/4 y for +ve y x<y but for -ve y x>y not sufficient
St.2: |y - x| = x - y --> y-x <=0 --> x>=y not sufficient

combined : x=y case is removed====sufficient

Ans C

[girish3131]

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[girish3131]

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