Quadratic Equation

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Quadratic Equation

by harsh.champ » Fri Feb 19, 2010 9:48 am
(3x + 2) (2x - 5) = ax² + kx + n .
What is the value of a - n + k ?

A. 5
B. 8
C. 9
D. 10
E. 11
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by outreach » Fri Feb 19, 2010 10:00 am
(3x + 2) (2x - 5)=6x^2-11x-10

a=6
k=-11
n=-10

a - n + k=5

A

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by ajith » Fri Feb 19, 2010 12:21 pm
harsh.champ wrote:(3x + 2) (2x - 5) = ax² + kx + n .
What is the value of a - n + k ?

A. 5
B. 8
C. 9
D. 10
E. 11
(3x + 2) (2x - 5) = 6x^2 - 6x- 10
a=6 n = -10 k = -6
a-n =16
a -n +k = 10

D
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by harsh.champ » Fri Feb 19, 2010 12:44 pm
ajith wrote:
harsh.champ wrote:(3x + 2) (2x - 5) = ax² + kx + n .
What is the value of a - n + k ?

A. 5
B. 8
C. 9
D. 10
E. 11
(3x + 2) (2x - 5) = 6x^2 - 6x- 10
a=6 n = -10 k = -6
a-n =16
a -n +k = 10

D
Hey ajith,
You did a mistake over here.
(3x+2)(2x-5) = 6x^2-11x-10
but you have written
(3x+2)(2x-5) = 6x^2-6x-10
Thus,you got the wrong answer.Answer would be A not D.
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by shashank.ism » Sat Feb 20, 2010 7:34 am
harsh.champ wrote:(3x + 2) (2x - 5) = ax² + kx + n .
What is the value of a - n + k ?

A. 5
B. 8
C. 9
D. 10
E. 11
given equation is (3x + 2) (2x - 5) = ax² + kx + n
--> ax² + kx + n = (3x + 2) (2x - 5)
--> ax² + kx + n = 6x^2 -11x -10
so a=6 , k=-11, n= -10
so a-n+k = 6-(-10)+(-11)=5 Ans A
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