Ostrich or Tigers

[harsh.champ]

A zookeeper counted the heads of the animals in a zoo and found it to be 80. When he counted the legs of the animals he found it to be 260. If the zoo had only 2 animals- ostrich and tigers, how many tigers were there in the zoo?

(A) 30
(B) 40
(C) 50
(D) 60
(E) 70


The OA is C.

[ajith]

A zookeeper counted the heads of the animals in a zoo and found it to be 80. When he counted the legs of the animals he found it to be 260. If the zoo had only 2 animals- ostrich and tigers, how many tigers were there in the zoo?

(A) 30
(B) 40
(C) 50
(D) 60
(E) 70


The OA is C.

a - no of ostriches
b - number of tigers

a+b = 80
2a+4b = 260
a+2b = 130

b =50
a =30

[spoiler]No of tigers = 50[/spoiler]

[cunazza]

A zookeeper counted the heads of the animals in a zoo and found it to be 80. When he counted the legs of the animals he found it to be 260. If the zoo had only 2 animals- ostrich and tigers, how many tigers were there in the zoo?

(A) 30
(B) 40
(C) 50
(D) 60
(E) 70


The OA is C.

Let's build a system of equation:

(1) o + t = 80
(2) 2*o + 4*t = 260

o = (80-t). So 2*(80-t) + 4t = 260 => by solving per t you get t = 50.

The solution is C.

[shashank.ism]

A zookeeper counted the heads of the animals in a zoo and found it to be 80. When he counted the legs of the animals he found it to be 260. If the zoo had only 2 animals- ostrich and tigers, how many tigers were there in the zoo?

(A) 30
(B) 40
(C) 50
(D) 60
(E) 70


The OA is C.

Let X be the no. of ostrich and Y be the no. of tigers
So X+Y = 80
Also 2X+4Y = 260
[spoiler]Y = 50 Ans C[/spoiler]