value

[rahul.s]

if x is not = 0, then sqrt x^2/x = ?

(A) -1
(B) 0
(C) 1
(D) x
(E) |x| / x

i opted for C, but the OA is E

didn't quite understand why.

[sanjayism]

d) is correct answer

x^2/x =x

[papgust]

Here x can both -ve and +ve

sqrt (x^2) = +/- x = |x|

So, sqrt (x^2) / x = |x| / x (Choice E)

[thephoenix]

if x is not = 0, then sqrt x^2/x = ?

(A) -1
(B) 0
(C) 1
(D) x
(E) |x| / x

i opted for C, but the OA is E

didn't quite understand why.

x^2 ---> x can be -ve or +ve---->lxl

so x^2/x=lxl/x

another way is substitue x as 1,-1
for x=1; x^2/x=1
for x=-1;x^2/x=-1

which is smae as E

[mgmt_gmat]

HERE we don't know x>0 or x< 0. Hence sqrt(square of x) is |x|. that means +x or -x.

[shashank.ism]

if x is not = 0, then sqrt x^2/x = ?

(A) -1
(B) 0
(C) 1
(D) x
(E) |x| / x

i opted for C, but the OA is E

didn't quite understand why.

rahul if x is not 0 so x may be either positive or negative....
hence sqrt.(x^2) = |x| = x for x>0
and -x for x<0.
so, sqrt.(x^2)/x =[spoiler] |x|/x Ans E[/spoiler]