The average (arithmetic mean) of the 5 positive integers k,

[imane81]

thanks for your help on this one...

The average (arithmetic mean) of the 5 positive integers k, m, r, s, and t is 16, and k < m
< r < s < t. If t is 40, what is the greatest possible value of the median of the 5 integers?
A. 16
B. 18
C. 19
D. 20
E. 22

[harsh.champ]

thanks for your help on this one...

The average (arithmetic mean) of the 5 positive integers k, m, r, s, and t is 16, and k < m
< r < s < t. If t is 40, what is the greatest possible value of the median of the 5 integers?
A. 16
B. 18
C. 19
D. 20
E. 22

___________________________

k+m+r+s+t=16*5(80)
Now,t=40
=>k+m+r+s=40
Now,we know that the median of the 5 integers is r.
Since s>r
Therfore,minimum value of s will be r+1.
Hence,k+m+r+(r+1)=40
Also,since all the integers are positive,minimum value of k=1,m=2.
So,for maximum value of r, 1+2+r+(r+1)=40
=>2r+4=40
=>r=36/2=18

Hence,(B) should be the answer choice.

[ajith]

thanks for your help on this one...

The average (arithmetic mean) of the 5 positive integers k, m, r, s, and t is 16, and k < m
< r < s < t. If t is 40, what is the greatest possible value of the median of the 5 integers?
A. 16
B. 18
C. 19
D. 20
E. 22

(k+m+r+s+40)/5 =16

k+m+r+s = 40

the median is the value of r

it is maximum when k,m are minimum and r,s are maximum

k=1; m=2; r =r , s=r+1
3+2r+1 =40
r=18

The maximum median =18

[neelimareddym]

thanks for your help on this one...

The average (arithmetic mean) of the 5 positive integers k, m, r, s, and t is 16, and k < m
< r < s < t. If t is 40, what is the greatest possible value of the median of the 5 integers?
A. 16
B. 18
C. 19
D. 20
E. 22

IMO B

k+m+r+s+t = (16*5) = 80

So, k+m+r+s = 40

We are looking for the greatest possible value of r
So k=1,m=2 r+s = 37
r+s/2 =37/2 = 18.5
So r =18, s=19 will solve the case