BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach Starts Oct 17
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Chris Peckover, 100th-Percentile GMAT Scorer

Oct 17 · Chris Peckover
Sat · 11:00 AM to 2:00 PM ET
Oct 20 · Chris Peckover
Tue, Thu · 8:00 to 10:00 PM ET
Oct 25 · Josh Braslow
Sun · 1:00 to 4:00 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemand 5 seats left Start anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions
Start free 5-day trial
Read 559 reviewsTarget Test Prep

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

finding the last two digits

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
Source: — Problem Solving |
User avatar
Legendary Member
Posts: 1275
Joined: Thu Sep 21, 2006 11:13 pmFollowed by: 2 members
Location: Arabian Sea
Thanked: 125 times

by ajith » Mon Feb 01, 2010 11:38 pm
bhumika.k.shah wrote:Find the last 2 digits
65*29*37*63*71*87*62

1. 70
2. 30
3. 10
4. 90
5.94

OA D
The last digit will be 0 (5 and 2 are factors)
and the tens digit will be the last digit of
13*29*37*63*87*31 (dividing 65 by 5 and 62 by2)

Which is the last digit of 3*9*7*3*7*1
which is the last digit of 27*21*7
which is the last digit of 7*7
which is 9

so option D
Always borrow money from a pessimist, he doesn't expect to be paid back.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
GMAT Instructor
Posts: 3650
Joined: Wed Jan 21, 2009 4:27 amFollowed by: 80 members
Location: India
Thanked: 267 times
GMAT Score:760

by sanju09 » Mon Feb 01, 2010 11:57 pm
ajith wrote:
bhumika.k.shah wrote:Find the last 2 digits
65*29*37*63*71*87*62

1. 70
2. 30
3. 10
4. 90
5.94

OA D
The last digit will be 0 (5 and 2 are factors)
and the tens digit will be the last digit of
13*29*37*63*87*31 (dividing 65 by 5 and 62 by2)

Which is the last digit of 3*9*7*3*7*1
which is the last digit of 27*21*7
which is the last digit of 7*7
which is 9

so option D
That's harmonious, really!
The mind is everything. What you think you become. -Lord Buddha



Sanjeev K Saxena
Quantitative Instructor
The Princeton Review - Manya Abroad
Lucknow-226001

www.manyagroup.com
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Legendary Member
Posts: 941
Joined: Sun Dec 27, 2009 12:28 amFollowed by: 1 member
Thanked: 20 times

by bhumika.k.shah » Mon Feb 01, 2010 11:58 pm
genius!!! :)
ajith wrote:
bhumika.k.shah wrote:Find the last 2 digits
65*29*37*63*71*87*62

1. 70
2. 30
3. 10
4. 90
5.94

OA D
The last digit will be 0 (5 and 2 are factors)
and the tens digit will be the last digit of
13*29*37*63*87*31 (dividing 65 by 5 and 62 by2)

Which is the last digit of 3*9*7*3*7*1
which is the last digit of 27*21*7
which is the last digit of 7*7
which is 9

so option D
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Master | Next Rank: 500 Posts
Posts: 324
Joined: Thu Dec 24, 2009 6:29 amFollowed by: 1 member
Thanked: 17 times

by rahul.s » Tue Feb 02, 2010 1:52 am
ajith,

why'd u divide 65 and 62 by 5 and 2 resp?
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
Legendary Member
Posts: 1275
Joined: Thu Sep 21, 2006 11:13 pmFollowed by: 2 members
Location: Arabian Sea
Thanked: 125 times

by ajith » Tue Feb 02, 2010 1:58 am
rahul.s wrote:ajith,

why'd u divide 65 and 62 by 5 and 2 resp?
a. If a number is divisible by 5 and 2, the last digit is 0
b. The second last digit is the last digit of the number divided by 5 and 2

Example say you want to know the last two digits of 5*2*13*7*11

a. if we can divide the num by 5&2 the last digit is 0
b. the second last digit is the last digit of 13*7*11 which is 1

so last two digits of num is 10
Always borrow money from a pessimist, he doesn't expect to be paid back.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
GMAT Instructor
Posts: 3650
Joined: Wed Jan 21, 2009 4:27 amFollowed by: 80 members
Location: India
Thanked: 267 times
GMAT Score:760

by sanju09 » Tue Feb 02, 2010 1:59 am
rahul.s wrote:ajith,

why'd u divide 65 and 62 by 5 and 2 resp?
probably to take the only possible 10 as factor, out of it
The mind is everything. What you think you become. -Lord Buddha



Sanjeev K Saxena
Quantitative Instructor
The Princeton Review - Manya Abroad
Lucknow-226001

www.manyagroup.com
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1