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good question from GMATprep

Expert replies
by tanviet » Fri Jan 29, 2010 11:43 pm
there are 5 persons which are arranged in the round table. each arrangement is considered different from another when each's positions in an arrangement is different. Howmany are there arrangement.

120

24

60

80

70
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Source: — Problem Solving |

by thephoenix » Fri Jan 29, 2010 11:56 pm
IMO A

5*4!=120

4! for no. of circular arrangements
a person can take 5 position
therfor 5*4!
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by ajith » Sat Jan 30, 2010 1:04 am
duongthang wrote:each arrangement is considered different from another when each's positions in an arrangement is different.
That statement is ambiguous to me.

Is the question referring to absolute positions or relative positions?

Not quite sure!
Always borrow money from a pessimist, he doesn't expect to be paid back.
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by sars72 » Sat Jan 30, 2010 1:35 am
ajith wrote:
duongthang wrote:each arrangement is considered different from another when each's positions in an arrangement is different.
That statement is ambiguous to me.

Is the question referring to absolute positions or relative positions?

Not quite sure!
ajith, "each's positions in an arrangement is different" seems to imply absolute positions. In that respect, i guess the phoenix's solution is correct.
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by tanviet » Sun Jan 31, 2010 1:57 am
answer is 24, but I do not understand. this is from gmatprep. official source
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by ajith » Sun Jan 31, 2010 2:07 am
duongthang wrote:answer is 24, but I do not understand. this is from gmatprep. official source
In which case, what they meant was a simple circular permutation = (n-1)! = 4!

The question is very poorly worded though
Always borrow money from a pessimist, he doesn't expect to be paid back.
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by tanviet » Mon Feb 01, 2010 11:23 pm
there are 5 persons who seat around round table. How many different arrangement we can have? one arrangement is considered different from other arrangement if position of a person in a arrangement is different from position of that person in other arrangements

120
60
24
80
90

how to solve pls, help
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