ds w/ absolute value

[vasilisab]

What is the value of y?

(1) 3|x2 – 4| = y – 2

(2) |3 – y| = 11

[nkumar]

1 is ruled out at it includes another variable
2. there are two scenarios a. when (3-y)>0 and b. when (3-y) < 0
a. 3-y =11 => y= -8
b. -(3-y)= 11 => y=14
so, two different values of y
The answer should be E
Cheers

[gmatguy16]

but when you combine 1 and 2 you realize that y cannot be negative,it has to be positive..so only only value for y .answer should be c

[[email protected]]

Option 1 gives you the condition :
y - 2 > 0 or y > 2
Option 2 gives two answers
-8 and 14.

Combining both we get 14.
Hence C

[nkumar]

but when you combine 1 and 2 you realize that y cannot be negative,it has to be positive..so only only value for y .answer should be c

But mod (x2-4) can be negative when x2 is less than 4 for example when x is =0 or 1, x2-4 may have negative values as well, isn't it??

[kajcha]

|x^2-4| will always be positive...

[mallard906]

Also agree w/ C. Abs values are always positive...