help please

[jgmat2010]

1.
Five bells begin to toll together and toll respectively at intervals of 6,7,8,9 and 12 seconds. How many times, will they toll together in one hour excluding the one at the start?


a. 5 b. 6 c. 7 d. 4 e. None of these

2.
A two digit number is such that the unit digit multiplied by 3 is equal to three more than the sum of the digits. When the digits are reversed the resulting number is 18 less than the original number. Find the units digit of the original number.


a. 8 b. 5 c. 4 d. 2 e. 1

3.
When an integer 'n' is divided by 'k', the remainder is one. When another integer 'm' is divided by 'k', the remainder is 2. What is the remainder when 'n x m' is divided by 'k'?


a. 1 b. 2 c. 3 d. n-1 e. n/2

[ajith]

1.
Five bells begin to toll together and toll respectively at intervals of 6,7,8,9 and 12 seconds. How many times, will they toll together in one hour excluding the one at the start?


a. 5 b. 6 c. 7 d. 4 e. None of these

2.
A two digit number is such that the unit digit multiplied by 3 is equal to three more than the sum of the digits. When the digits are reversed the resulting number is 18 less than the original number. Find the units digit of the original number.


a. 8 b. 5 c. 4 d. 2 e. 1

3.
When an integer 'n' is divided by 'k', the remainder is one. When another integer 'm' is divided by 'k', the remainder is 2. What is the remainder when 'n x m' is divided by 'k'?


a. 1 b. 2 c. 3 d. n-1 e. n/2

First of all, Please post one question per thread it will help potential searchers in the future and it will help you to track the answers better.

1. There are 3600 seconds in an hour. LCM of 6,7,8,9 and 12 is 504, meaning they will toll together once in 504 seconds. 7 is the answer
2. ab be the num ; 3b =3+a+b; 10a+b = 10b+a+18

2b = a+3 a-b =2 solving b=5 a=7

3. n =ka+1 m =kb+2
mn =k^2ab+ 2ka+kb+2
so the remainder will be 2

[jgmat2010]

Thanks ajith, i will post only one next time