Integers A and B

[yserious]

Any help here?
How to go about this?The OA seems to be B

[linkinpark]

are you sure its B?

IMO its C

from stm1 and stmt2 we get 2 values of a and b hence both not sufficient, using both, we can pick 1 value of a and b.

[sunil_snath]

from stmt1, we get

a^3-a^2-b = 49
a(a^2-a)-b = 49
12a-b = 49 => NOT SUFFICIENT

from stmt2, we get

b^2-b-2 = 0
b = 2, -1

now only when b=-1 will we get an integer value of a = 4, so stmt2 is SUFFICIENT

So i think thats how we get B, but without the ans i would have chosen C as well

[ramsharma]

from stmt1, we get

a^3-a^2-b = 49
a(a^2-a)-b = 49
12a-b = 49 => NOT SUFFICIENT

from stmt2, we get

b^2-b-2 = 0
b = 2, -1

now only when b=-1 will we get an integer value of a = 4, so stmt2 is SUFFICIENT

So i think thats how we get B, but without the ans i would have chosen C as well

I would like to add a bit

For Statement 1:a^2-a=12.The statement itself gives the value of"a".but it gives two values -3,and 4.hence not sufficient

explanation of statement 2 is explained well by Sunil;