function

[hpgmat]

if x and y are integers greather than 1 , is x a multiple of y?

1) 3(y^2) + 7y = x

2) x^2- x is multiple of y

my approach :

x multiple of y translates to : is X = A Y ??

1) Y (3Y+7) = X ....> now x is written as AY ( with (3Y + 7) being A)

2) x^2 - x = B Y ....> x (x-1) = B Y ...> X = (B/(x-1)) Y ....> X is written as AY ( with B/(x-1) being A

[bou_k]

you have a problem B/(x-1)) is not an integer in general so the ans is only A)

[adamsmith2009]

A) Not sufficient. X could be 3 which would make Y= 34 or X could be 2 which would make Y= 20.

B) Sufficient. x(x-1) = multiple of Y

So if x is 3 y is a multiple of 6. Therefore the minimum number y could be would be 6. So x can't be a multiple of y.
If x is 5 y is a multiple of 20. Therefore the minimum number y could be would be 20. So x can't be a multiple of y. X is always less than Y.

What's the OA?

[November Rain]

Hi
I think it's E. Could you please let us know the OA?

A is insufficient - If you add two numbers multiple of Y and theresult is a multiple of X doesn't mean that Y is a multiple of X on its own.

B is also insufficient - It can be rephrased into x(x-1) is a multiple of Y. However, the number that can allow Y to become multiple of x(x-1) might be X-1 or X. So, also insufficient.

Both statements together don't seem to add any new information to each other. So, its E.

Could anyone confirm the OA?

[hpgmat]

A) Not sufficient. X could be 3 which would make Y= 34 or X could be 2 which would make Y= 20.

B) Sufficient. x(x-1) = multiple of Y

So if x is 3 y is a multiple of 6. Therefore the minimum number y could be would be 6. So x can't be a multiple of y.
If x is 5 y is a multiple of 20. Therefore the minimum number y could be would be 20. So x can't be a multiple of y. X is always less than Y.

What's the OA?

you are thinking x factor of y . question is saying x multiple of y