(v-3)t = (v+3)(t-0.5) = 90
(v+3)/(v-3) = t/(t-.5)
2v/6 = 2(2t-.5) = 4t - 1
v = 12t-3
(12t-6)t = 90
(2t-1)t = 15 = 5.3
t = 3 (upsteam)
downstream = 2.5
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Floating Down a River - How Would You Solve It?
Source: Beat The GMAT — Problem Solving |
How'd you move from "(v+3)/(v-3) = t/(t-.5)" to "2v/6 = 2(2t-.5)"?palvarez wrote:(v-3)t = (v+3)(t-0.5) = 90
(v+3)/(v-3) = t/(t-.5)
2v/6 = 2(2t-.5) = 4t - 1
v = 12t-3
(12t-6)t = 90
(2t-1)t = 15 = 5.3
t = 3 (upsteam)
downstream = 2.5
a/b = c/d
(a+b)/(a-b) = (c+d)/(c-d)
a/b = c/d
add 1 both sides
(a+b)/b = (c+d)/d
subtract 1 both sides
(a-b)/b = (c-d)/d
Divide both
(a+b)/(a-b) = (c+d)/(c-d)
(a+b)/(a-b) = (c+d)/(c-d)
a/b = c/d
add 1 both sides
(a+b)/b = (c+d)/d
subtract 1 both sides
(a-b)/b = (c-d)/d
Divide both
(a+b)/(a-b) = (c+d)/(c-d)
