BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach Starts Oct 17
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Chris Peckover, 100th-Percentile GMAT Scorer

Oct 17 · Chris Peckover
Sat · 11:00 AM to 2:00 PM ET
Oct 20 · Chris Peckover
Tue, Thu · 8:00 to 10:00 PM ET
Oct 25 · Josh Braslow
Sun · 1:00 to 4:00 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemand 5 seats left Start anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

Probability Q

Expert replies
Source: — Problem Solving |

by satish.nagdev » Fri Oct 30, 2009 9:43 pm
IMO C
(7C4)*(1/2^7)
Wounded by GMAT but not dead
Join the discussion

by punitkaur » Sat Oct 31, 2009 6:52 am
The answer is correct. Could you provide explanation please?

Thanks
Join the discussion

by satish.nagdev » Sat Oct 31, 2009 7:16 am
7C4 = number of combinations of days with rain and no rain say x=rainy day, y = non-rainy
so we can have a pattern xyxyxyx....
and probability for either case is 1/2 (50%) so for 7 days it will be 1/2*1/2...7 times = (1/2^7)

I came across other way to solve it using binomial probability distribution formula as well

P(f) = nCr * P(rainy day) * (1 - P(rainy day))^n-r
where n = 7 and r = 4 and P(rainy day) = 1/2
Wounded by GMAT but not dead
Join the discussion

by punitkaur » Sat Oct 31, 2009 7:50 am
Got it ... Thanks!!
Join the discussion

by life is a test » Sun Nov 01, 2009 6:31 am
satish.nagdev wrote:7C4 = number of combinations of days with rain and no rain say x=rainy day, y = non-rainy
so we can have a pattern xyxyxyx....
and probability for either case is 1/2 (50%) so for 7 days it will be 1/2*1/2...7 times = (1/2^7)

I came across other way to solve it using binomial probability distribution formula as well

P(f) = nCr * P(rainy day) * (1 - P(rainy day))^n-r
where n = 7 and r = 4 and P(rainy day) = 1/2
I misread the question to mean that it rains on 4 consecutive days out of the 7 - for this would the answer be 4C3 * 0.5^7?

thks.
Join the discussion

by fireplayer » Sun Nov 08, 2009 8:33 am
satish.nagdev

i agree with u
Join the discussion

by sanjana » Mon Nov 09, 2009 6:57 pm
Whenever an event has a 50% chance of occuring,it can always be treated as a flipping of a coin question.
This question is the same as "what is the probability of getting 4H on 7 flips of a coin"

You can apply the formula :
P(k results on n flips) = nck/2^n

Here,K=4,N=7 and the answer on substitution is 35/128.
Join the discussion