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uptowngirl92
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|x| < 1?
Source: Beat The GMAT — Data Sufficiency |
IMO C
statement 1) gives x=3,1/3 not suff
statement 2) gives x#3 and x#-3
combining x=1/3
hence mod X<1
OA pls
statement 1) gives x=3,1/3 not suff
statement 2) gives x#3 and x#-3
combining x=1/3
hence mod X<1
OA pls
It does not matter how many times you get knocked down , but how many times you get up
How does |x-3|#0 imply that x#3 and x#-3??xcusemeplz2009 wrote:IMO C
statement 1) gives x=3,1/3 not suff
statement 2) gives x#3 and x#-3
combining x=1/3
hence mod X<1
OA pls
If x=-3 |x-3| = |-3-3| = |-6| = 6#0
even I think its E.
1) |x + 1| = 2|x - 1|sanjana wrote:How does |x-3|#0 imply that x#3 and x#-3??xcusemeplz2009 wrote:IMO C
statement 1) gives x=3,1/3 not suff
statement 2) gives x#3 and x#-3
combining x=1/3
hence mod X<1
OA pls
If x=-3 |x-3| = |-3-3| = |-6| = 6#0
even I think its E.
x+1 = 2x-2 or x+1 = -2x+1 --> x = 3 or 1/3
2) says that x cannot =3 hence it must = 1/3 so IMO C
1) |x + 1| = 2|x - 1|
x+1 = 2x-2 or x+1 = -2x+1 --> x = 3 or 1/3
If x is -ve. shouldn't the equation be -
-x - 1 = -2x+1 ?????
Please correct if I am wrong?
x+1 = 2x-2 or x+1 = -2x+1 --> x = 3 or 1/3
If x is -ve. shouldn't the equation be -
-x - 1 = -2x+1 ?????
Please correct if I am wrong?
life is a test wrote:1) |x + 1| = 2|x - 1|sanjana wrote:How does |x-3|#0 imply that x#3 and x#-3??xcusemeplz2009 wrote:IMO C
statement 1) gives x=3,1/3 not suff
statement 2) gives x#3 and x#-3
combining x=1/3
hence mod X<1
OA pls
If x=-3 |x-3| = |-3-3| = |-6| = 6#0
even I think its E.
x+1 = 2x-2 or x+1 = -2x+1 --> x = 3 or 1/3
2) says that x cannot =3 hence it must = 1/3 so IMO C
