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People chosing integers

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by caspermonday » Mon Oct 26, 2009 10:28 am
As a part of a game, four people each much secretly chose an integer between 1 and 4 inclusive. What is the approximate likelihood that all four people will chose different numbers?

OA [spoiler]3/32[/spoiler]
Please explain
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Source: — Problem Solving |

by caspermonday » Mon Oct 26, 2009 10:30 am
Oh, I got it!
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by xcusemeplz2009 » Mon Oct 26, 2009 10:32 am
total no of possibility is 4*4*4*4

desirable possibilty is 4!

so probability is 4!/4^4=3/32
It does not matter how many times you get knocked down , but how many times you get up
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