If |x|·y+ 9 > 0, and x and y are integers, is x < 6?
(1) y is negative
(2) |y| < 1
"Stmnt 2 - Insufficient - Since the question stem tells us that y is an integer, the statement |y| ≤ 1 implies that y equals -1, 0, or 1. Substituting these values for y into the expression |x|·y > -9, we see that x could be less than 6, greater than 6, or even equal to 6. This is particularly obvious if y = 0; in that case, x could be any integer at all. (You can test this by picking actual numbers.)"
can someone explain the underlined portion? bcoz as far as I knw, if y<=1, Y can be 1,0,-1,-2....
thanks[/b]
(1) y is negative
(2) |y| < 1
"Stmnt 2 - Insufficient - Since the question stem tells us that y is an integer, the statement |y| ≤ 1 implies that y equals -1, 0, or 1. Substituting these values for y into the expression |x|·y > -9, we see that x could be less than 6, greater than 6, or even equal to 6. This is particularly obvious if y = 0; in that case, x could be any integer at all. (You can test this by picking actual numbers.)"
can someone explain the underlined portion? bcoz as far as I knw, if y<=1, Y can be 1,0,-1,-2....
thanks[/b]
