Stacy and heather are 20 miles apart and walk towards each other on the same route. Stacy walks at a constant rate that is 1 mile per hour faster than Heather's constant rate of 5miles/hour. If Heather starts her journey 24 minutes after Stacy, how far from her original destination has Heather walked when the two meet?
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8
9
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11
OA B
how do u solve the sum with the sum of rates method (i.e here the sum of rates is 11)
My procedure was.. In 24 min S walks 24/60*6= 2.4 MILES
thus, the two will meet in (20-2.4)/(5+6) hours = 19.6/11 hrs
in this time, H must have walked (19.6/11)*5 = 8.9 miles...
Where did I go wrong??
thanks
7
8
9
10
11
OA B
how do u solve the sum with the sum of rates method (i.e here the sum of rates is 11)
My procedure was.. In 24 min S walks 24/60*6= 2.4 MILES
thus, the two will meet in (20-2.4)/(5+6) hours = 19.6/11 hrs
in this time, H must have walked (19.6/11)*5 = 8.9 miles...
Where did I go wrong??
thanks
