BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach Starts Oct 17
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Chris Peckover, 100th-Percentile GMAT Scorer

Oct 17 · Chris Peckover
Sat · 11:00 AM to 2:00 PM ET
Oct 20 · Chris Peckover
Tue, Thu · 8:00 to 10:00 PM ET
Oct 25 · Josh Braslow
Sun · 1:00 to 4:00 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemand 5 seats left Start anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

Testprep2

Expert replies
by moneyman » Sat Sep 01, 2007 5:46 am
Which of the following inequalities has a solution set that,when graphed on the number line,is a single line segment of finite length??

x^4>and=1
x^3<and=27
x^2>and=16
2<=|x|<=5
2<=3x+4<=6
Maxx
Join the discussion
Source: — Problem Solving |

by agps » Sat Sep 01, 2007 6:40 am
hmmm, let's see.
Answer B

why?

D, and E sound like they're out, but let's check.

D) 2 <= |x| <= 5, this translates to |x|>=2 and |x|<=5
x>=2 or x<=-2 and x<=5 or x>=-5 so x is between -5 and -2 or between 2 and 5, not a infinite length line segment.

E) 2<=3x+4<=6
2-4<=3x+4-4<=6-4
-2<=3x<=2
-2/3<=x<=2/3 also not a infinite length line segment.

***on test day, if an option looks as it's not the one focus on the others first, try not to waste your time, but for practise sake i ruled them out***

so, why not A or C
A and C are true for positive and negative numbers.
in A all values greater than 1 and smaller than -1 will funtion here, so the line would break between theese numbers.
in C all values greater than 4 and smaller than -4 will funtion here, so the line would break between theese numbers.

B is the only inequality that has a single infinite line segment, from -infinity to 3.
Join the discussion

by moneyman » Sat Sep 01, 2007 11:21 pm
No the answer is e
Maxx
Join the discussion

Re: Testprep2

by jaspreet.sharma » Tue Sep 04, 2007 3:30 pm
moneyman wrote:Which of the following inequalities has a solution set that,when graphed on the number line,is a single line segment of finite length??

x^4>and=1
x^3<and=27
x^2>and=16
2<=|x|<=5
2<=3x+4<=6



x^4>and=1 = X can be 1,2…..any int so not a line segment
x^3<and=27 implies x can be 1,2 or 3 so not a line segment
x^2>and=16 implies x can be 4,5,……any int greater than 4 and negative int can also be the value for x
2<=|x|<=5 implies -2>=x>=2 and -5<=x<=5 so, x has many values
2<=3x+4<=6 implies true for just 1 value of x i.e. x=0 so ……it has fixed length

SO the answer is E

I hope it explained it well
Join the discussion

by agps » Wed Sep 05, 2007 2:44 am
you're right, don't know what i was thinking on that day, any range of numbers squared or cubed will never yield a consecutive set of results, A,B & C out.

and from my own previous answer
E) 2<=3x+4<=6
2-4<=3x+4-4<=6-4
-2<=3x<=2
-2/3<=x<=2/3 also not a infinite length line segment.

but since we're looking for a finite line segment. I need to take more care with reading what is asked :evil:
Join the discussion