OG 11 porblem 119

[ershovici]

Is 2x-3y < x sqr
1) 2x - 3y = -2
2) x>2 and y>0

IMO answer is C, but OA is Dcan someone explain me because I have no explanation

[Pugalenthi]

Evaluate statement 1: 2x - 3y = -2
based on the given information, Y is greater than X. Else the resulting value would not be negative.
so, the question is -2 < X sqr. Given that X sqr will always be positive, statement A answers the question.

Evaluate statement 2:x>2 and y>0

pick some numbers:
If x=3; y= 5;
2(3) - 3(15) < 9
6 - 45 < 9
-39 < 9 - yes

If x=3; y = 1;
2(3) - 3(1) < 9
6 - 3 < 9
3 < 9
hence statement B answers the question.

The final answer to this question is D

[sanjana]

Is 2x-3y< X^2

From (1) we have

-2<x^2

This is sufficient as the square of a number will always be +ve

From (2)
The given equation can be written as

is x^2-2x+3y > 0 ?

is x(x-2) + 3y > 0 ?

If x>2
then x(x-2) will be greater than 0

And if y>0,3y will be greater than 0
Hence sufficient

Therefore D