What is the median?

[ern5231]

There are 50 continuous integers in a series. What is the median of the series?

a) Max number is 25
b) Sum of the biggest and the smallest number is 1

[engg.manik]

If the max number is 25 then the series should be

from -24, -23 ,-22 ..... 0 , 1 , ...25.

It also satisfies the second condition min + max = 1.

Now the median will be (0 + 1)/ 2 = 0.5

[ern5231]

This is a DS question. The OA given is D but I feel the answer is A.

[Brent@GMATPrepNow]

There are 50 continuous integers in a series. What is the median of the series?

a) Max number is 25
b) Sum of the biggest and the smallest number is 1

(a)From here we can determine that the numbers range from -24 to 25. Since we know all 50 numbers, we can determine the median --> SUFF

(b) let x = the smallest integer
x+1 = 2nd integer
x+2 = 3rd integer
.
.
.
x+49 = 50th (last) integer
From the statement we can write the equation x + (x+49)=1
We can solve this equation to get x=-24.
Now that we know the first number is -24, we can determine that the last number is 25.
Since we know all 50 numbers, we can determine the median --> SUFF

Answer=D

[ern5231]

Thanks Brent but suppose we have a series : -49 to 0 then the median is not the same as obtained above. In that case the again the answer should be A. Where am I going wrong?

[Brent@GMATPrepNow]

Thanks Brent but suppose we have a series : -49 to 0 then the median is not the same as obtained above. In that case the again the answer should be A. Where am I going wrong?

Are you suggesting that the set of numbers from -49 to 0 satisfy the condition set out in statement (2)?
Here, the sum of the biggest and smallest numbers is not 1