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by gmat20092009 » Mon Sep 21, 2009 10:31 am
three cans consist of 06 green, 09 red and 13 black ball. What is the MIN no. of balls we can withdraw so that we have two balls of each colour?

Three cans consist of 06 green, 09 red and 13 black ball. What is the MAX no. of balls we can withdraw so that we have two balls of each colour?
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Source: — Problem Solving |

by mp2437 » Mon Sep 21, 2009 11:19 am
question 1:If you are very lucky, you will pull out 2 green, 2 red, and 2 black right away, so minimum = 6.

maximum is 24. If you are very unlucky, you will pull out 13 black, followed by 9 red, and then the first 2 green, so 13 + 9 + 2 = 24.
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