How many integers from 0 to 50, inclusive, have a remainder of 1 when divided by 3 ?
A. 15
B. 16
C. 17
D. 18
E. 19
[spoiler]Its 3k+1
k=0> 1
k=1>4
k=2>7
.
.
.
k=16>49
Therefore,should'nt the answer be 16?Please clarify.[/spoiler]
remainder of 1 when divided by 3
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you have used the method correctly but when u r counting,
3*0+1=1
3*1+1=4
..
3*16+1=49
u are taking the last '16' as the answer but u're not including the first '0' also into the count
so it should be 16+1=1
3*0+1=1
3*1+1=4
..
3*16+1=49
u are taking the last '16' as the answer but u're not including the first '0' also into the count
so it should be 16+1=1