2^[(4-1)^2] / [2/^(3-2)]

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2^[(4-1)^2] / [2/^(3-2)]

by doclkk » Mon Aug 31, 2009 1:48 pm
2^[(4-1)^2] / [2/^(3-2)]

a. 2^8
b. 2^7
c. 2^6
d. 2^5
e. 2^4

OA (A)

I disagree with OA. An exponent to an exponent means you would multiply. So it would be 2^6 / 2^1 = 2^5.

I got these questions from the 700+ document but I'm guessing that it could be wrong?

What is an instance where you're actually exponenting and exponent.
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by tohellandback » Mon Aug 31, 2009 7:25 pm
there is a difference between

(a^b)^c and a^(b^c)
(a^b)^c will be a^(bc)
but for a^(b^c), you first need to calculate b^c because of the brackets.

and IMO OA given is right
The powers of two are bloody impolite!!