condition 1) means x+y is less than 1 because when a is positive integer greater than 1 the only way to make it less than 1 is to have negative power.ern5231 wrote:Given that a>1 and b>1. Is (a^x)(b^y)<1?
(1) a^(x+y) < 1
(2) b^(x+y) < 1
Same is implied by condition 2).
However we cannot deduce anything useful from x+y being negative for the question because we do not know the sign of each x and y.
Hence IMO E
