BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach Starts Oct 17
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Chris Peckover, 100th-Percentile GMAT Scorer

Oct 17 · Chris Peckover
Sat · 11:00 AM to 2:00 PM ET
Oct 20 · Chris Peckover
Tue, Thu · 8:00 to 10:00 PM ET
Oct 25 · Josh Braslow
Sun · 1:00 to 4:00 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemand 5 seats left Start anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

x/3

Expert replies
Source: — Data Sufficiency |

by vikram_k51 » Tue Aug 04, 2009 11:45 am
a/b + b/a is always >=2

Since A.M >= G.M

Thus (a/b+b/a)/2>=Sqrt(a/b*b/a)

Or a/b+b/a >=2

This is always true.So how is this a D.S question?
Join the discussion

Re: x/3

by shahdevine » Tue Aug 04, 2009 2:09 pm
Sher1 wrote:Is x/3+3/x>2

1 x<3

2 x>1
rewrite given statement

(x^2+9)/3x>2
x^2+9>6x
x^2-6x+9>0

is (x-3)^2>0?

the answer is yes if we know that x>3

statement 1)

x<3 so sufficient

statement 2)

x>1 ---> x could be less than 3 and greater than 3. insufficient

A is answer

you got this!
Join the discussion

by shahdevine » Tue Aug 04, 2009 2:10 pm
vikram_k51 wrote:a/b + b/a is always >=2

Since A.M >= G.M

Thus (a/b+b/a)/2>=Sqrt(a/b*b/a)

Or a/b+b/a >=2

This is always true.So how is this a D.S question?
where did you get this? good to know, if true.
Join the discussion

by Sher1 » Tue Aug 04, 2009 3:31 pm
This is a question I got in GMAT Focus and the OA is C

I also incorrectly got A. Didnt like their explanation so thought if there is a better way to tackle this.
Join the discussion

by pandeyvineet24 » Tue Aug 04, 2009 3:52 pm
Stmt 1 is not sueffecient for the negative values of X
If X = -1, the sum of X/3 + 3/X is negative and hence less than 2
If X = 2, the sum 2/3 + 3/2 = .66 + 1.5 = 2.1 which is greater than 2
Insufficient

Stmt 2
If X = 2, the sum 2/3 + 3/2 = .66 + 1.5 = 2.1 which is greater than 2
If X = 3, the sum 3/3 + 3/3 =2 which is not greater than 2
Insufficient

Combine together 1 < x< 3 C is sufficient
Join the discussion

by tom4lax » Wed Aug 05, 2009 6:41 pm
So I got this question correct. I converted the original question into:

(x^2+9)/3x > 2, then plugged in numbers to test the two conditions.

For Stmt 1, positive and negative values render the stmt insufficient using the equation above.

However, I could certainly see myself converting the original question into the following (x-3)^2 > 0. This is what I don't understand. It seems as though here any number greater than 3 satisfies the requirement, so answer would be A.

Thoughts?
Join the discussion

by tohellandback » Wed Aug 05, 2009 9:39 pm
shahdevine wrote:
vikram_k51 wrote:a/b + b/a is always >=2


Since A.M >= G.M

Thus (a/b+b/a)/2>=Sqrt(a/b*b/a)

Or a/b+b/a >=2

This is always true.So how is this a D.S question?
where did you get this? good to know, if true.
IMO C

yeah this is always true:
A.M>=G.M>=H.M
the equality is true when a/b=b/a
in the question
x/3+3/x>=2 , equality holds when x/3=3/x, i.e X=3 or -3

1)x<3, x can be -3 not sufficient
2) x>1, X can be 3, not sufficient

combines 1<X<3, X cannot be equal to 3 or -3. sufficient
The powers of two are bloody impolite!!
Join the discussion