can anyone solve this data sufficiency ques

[jagmohi]

Any decimal that has only a finite number of nonzero digits is a terminating decimal. For example, 36, 0.72, and 3.005 are terminating decimals.
If a, b, c, d and e are integers and p = 2^a3^b and q = 2^c3^d5^e, is p/q a terminating decimal?




(1) a > c

2) b>d

[mike22629]

IMO B.

The rule for terminating decimals is that the denominator must only have factors of 2 and 5.

So,
if B is bigger than D, than there are no factors of 3 in the denominator. Only factors of 2 and 5, making the number terminating.

[gmat_2010]

I am sorry, I couldn't follow the question. From what I understand, 2 raised to any integral power (positive, negative, 0) will always yield a terminating decimal when divided by another such exponential value of 2. Doesn't matter what the integral exponents are in the numerator and the denominator. I think I couldn't understand the problem. Can anyone explain?