Math Question

[rxs1208]

Hello All,

FOr the following question,can you please let me know how to get the solution.

A group of n students can be divided into equal groups of 4 with 1 student left over or equal groups of 5 with 3 students left over. What is the sum of the two smallest possible values of n?


Answer : 46

Thanks
Rakesh

[wanttobeat]

We can go up the multiples of 4 and add 1 to each and then deduct 3 to determine if it is divisible by 5. For eg. the third multiple of 4 is 12. Add 1 to 12 and the resulting number 13 leaves a remainder of 3 when divided by 5.

This way we can get the two least values of n: 13 and 33. Thus we derive the answer: 13+32 = 46.