which of the following cannot be the median

[uptowngirl92]

which of the following cannot be the median of the three ordered positive integers x,y and z?
x
z
x+z
x+z/2
x+z/3

I got the correct answer (c) but was thrown off-guard by the word "ordered".What does it mean?At first glance I thought it mens that they are ordered in ascending/descending but i guess not!!Please shed some light.

[ssmiles08]

I think you are right. I think it does mean ordered, but I dont think it is strictly ascending or descending, it could also mean that some variables are the same?

1) 4, 4, 5 works
2) 5, 7, 7 works
3) does not work b/c y is median which should be >= x or <= z.
4) 3, 4, 5 works
5) 3, 3, 6 works

[batman73]

which of the following cannot be the median of the three ordered positive integers x,y and z?
x
z
x+z
x+z/2
x+z/3

I got the correct answer (c) but was thrown off-guard by the word "ordered".What does it mean?At first glance I thought it mens that they are ordered in ascending/descending but i guess not!!Please shed some light.

According to OG 11, the word "ordered" is not stated in the problem. Does this mean that OG made a mistake, because I did not assume they are ordered because it is not mentioned. Can someone help me with this? Thanks in advance

[tohellandback]

ordered means in order. ascending or descending
but in any case median can only be >= smallest number and <= greatest number
x+z is greater than Z

as for batman73's question, even if they are not ordered, its impossible
lets say 3 numbers x,y and z
IF, x+z is the median
then y must be equal to x+z because thats the only number remaining since neither x nor z is the median.
that means y>=x or x+z>=x-true
but
that also means y<=z or X+Z<=Z- false if all numbers are positive