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by kanha81 » Sun Jun 07, 2009 1:16 pm
Half the people on a bus get off at each stop after the first, and no one gets on after the first stop. If only one person gets off at stop number 7, how many people got on at the first stop?

A. 128
B. 64
C. 32
D. 16
E. 8
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Source: — Problem Solving |

by ssmiles08 » Sun Jun 07, 2009 1:31 pm
I got (B) as my answer.

If x people got on the bus at 1st stop,

x/2 get off the 2nd stop
x/4 get off the 3rd stop
x/8 - 4th stop
x/16 - 5th stop
x/32 - 6th stop
x/64 - 7th stop

x/64 = 1

x = 64

64 people get on @ the first stop.
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by PAB2706 » Mon Jun 08, 2009 6:22 am
i got 16 as my answer...

:shock:

wht is the OA?
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by kanha81 » Mon Jun 08, 2009 6:46 am
PAB2706 wrote:i got 16 as my answer...

:shock:

wht is the OA?
OA is 64
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Always do what you're afraid to do. Whoooop GMAT
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by ghacker » Mon Jun 08, 2009 11:36 am
The question is about binary numbers

Lets name the Halts A,B,C,D,E,F and G , G is the final halt , and in other nobody got in but half got out
so if we look at it like this

A B C D E F G
2^6 = 64 .............. 2^0 =1

Ans =2^6 = 64
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by PAB2706 » Mon Jun 08, 2009 4:26 pm
oh freak!!! :shock:

i mistook the question.....

cool....
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