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Guava extract

Expert replies
by kanha81 » Sat May 30, 2009 11:53 am
Joaquin is inventing a new juice drink. Joaquin combines 15 liters of a juice mix that contains 20% guava extract, with a 20 liter bottle of a different fruit juice mix. If the resulting concoction contains 18% guava extract, what was the original percent of guava extract in the 20-liter bottle of fruit juice mix?

A) 21%
B) 18%
C) 16.5%
D) 15.2%
E) 13.4%
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Source: — Problem Solving |

by truplayer256 » Sat May 30, 2009 12:01 pm
The 15 liters of the juice mix contains 3 liters guava extract. Let x represent the amount of guava extract in the 20 liter bottle of different juice mix.

3+x/35=9/50
150+50x=315
165/50=3.3

Now to find what percent of 20 gives 3.3:

20(x)/100=3.3
x=16.5% C.
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by blackarrow » Sat May 30, 2009 1:53 pm
Another method thru formula

Basically equating the strength of the mixtures to get the result

15(20%-18%)= 20(18/100-x%)

3/10=(18-100x)/5

ans 16.5

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by exhilaration » Sat May 30, 2009 2:07 pm
truplayer256 wrote:The 15 liters of the juice mix contains 3 liters guava extract. Let x represent the amount of guava extract in the 20 liter bottle of different juice mix.

3+x/35=9/50
150+50x=315
165/50=3.3

Now to find what percent of 20 gives 3.3:

20(x)/100=3.3
x=16.5% C.
Why is it equal to 9/50?
Join the discussion

by ssmiles08 » Sat May 30, 2009 3:24 pm
exhilaration wrote:
truplayer256 wrote:The 15 liters of the juice mix contains 3 liters guava extract. Let x represent the amount of guava extract in the 20 liter bottle of different juice mix.

3+x/35=9/50
150+50x=315
165/50=3.3

Now to find what percent of 20 gives 3.3:

20(x)/100=3.3
x=16.5% C.
Why is it equal to 9/50?

Because 9/50 is 18/100 (18%)simplified.
Join the discussion