n divisible by 6?

[crackgmat007]

If n and k are positive integers, is n divisible by 6?
(1) n = k(k + 1)(k - 1)
(2) k – 1 is a multiple of 3.

Is statement 1 alone is sufficient? Can anyone clarify this pls? Tx much.

[aj5105]

Statement (1): You cannot consider 0,1,2. Though 1,2 are positive, the product (n) becomes 0.

Consider any three consecutive numbers[ k-1, k, k+1] such as 1, 2, 3 or 2, 3, 4 or 4, 5, 6 ... Their product is divisible by 6.

(A)

[mike22629]

You can also consider k=1

0 is divisible by any number or 0 is a multiple of every number.

IMO B.

Furthermore, think of the equation in the first statement

It is telling you that n = the product of three consecutive numbers

A number is divisible by 6 is it is divisible by 3 and by 2. Three consecutive positive numbers will always meet this requirement.

[iamcste]

You can also consider k=1

0 is divisible by any number or 0 is a multiple of every number.

IMO B.

Furthermore, think of the equation in the first statement

It is telling you that n = the product of three consecutive numbers

A number is divisible by 6 is it is divisible by 3 and by 2. Three consecutive positive numbers will always meet this requirement.

IMO AHow can it be B

In Stmt 2, we have only information only about K. How does it help you to determine divisibility of n by 6. means you considered information stated in stmt 1 without knowing

[iamcste]

You can also consider k=1

0 is divisible by any number or 0 is a multiple of every number.

.

when you select K=1, n becomes 0...and as per info given, n is a positive integer...and hence it cant be 0, Note: 0 is neither positive nor negative

HTH