Let Remainders Flee You on the Exam

[dtweah]

The remainder of the division of (1! + 2! + 3! + … + 17!) by 6 is
(a) 1
(b) 2
(c) 3
(d) 4
(e) 5

[cramya]

3

1!+2! = 3

The rest all give a remainder 0 i.e. starting from 3!

[sureshbala]

3

1!+2! = 3

The rest all give a remainder 0 i.e. starting from 3!

Perfect....