BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach Starts Oct 17
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Chris Peckover, 100th-Percentile GMAT Scorer

Oct 17 · Chris Peckover
Sat · 11:00 AM to 2:00 PM ET
Oct 20 · Chris Peckover
Tue, Thu · 8:00 to 10:00 PM ET
Oct 25 · Josh Braslow
Sun · 1:00 to 4:00 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemand 5 seats left Start anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

A large wooden cube... (probability)

Expert replies
by avenus » Sun May 03, 2009 4:24 am
A large wooden cube, measuring 10 cm on an edge, is composed of smaller cubes, each measuring 1 cm on an edge. The entire outside surface of the assembled large wooden cube is painted red, and the disassembled, with all of the smaller, individual cubes placed in a drum. If one cube is selected randomly out of the drum, what is the probability that the cube selected will have at least one red face?

A. 12:25
B. 61:125
C. 1:2
D. 13:25
E. 3:5
Join the discussion
Source: — Problem Solving |

avenus wrote:A large wooden cube, measuring 10 cm on an edge, is composed of smaller cubes, each measuring 1 cm on an edge. The entire outside surface of the assembled large wooden cube is painted red, and the disassembled, with all of the smaller, individual cubes placed in a drum. If one cube is selected randomly out of the drum, what is the probability that the cube selected will have at least one red face?

A. 12:25
B. 61:125
C. 1:2
D. 13:25
E. 3:5
That's a tough one to visualize.
There are 1000 small cubes in total (10x10x10).
Each small cube within the inner 8x8x8 cube will have NO paint.

So, P(selecting a cube with NO paint) = (8^3)/1000
This means that P(selecting a cube with SOME paint) = 1 - (8^3)/1000 = 61/125 (answer choice B)
Brent Hanneson - Creator of GMATPrepNow.com
Image
Join the discussion

by lilu » Sun May 03, 2009 11:10 am
Thank you Brent!
Good question and great explanation! :D
The more you look, the more you see.
Join the discussion

by criszerriny » Mon May 04, 2009 11:12 am
how was 8x8x8 calculated?

Thanks
Join the discussion

by lilu » Mon May 04, 2009 12:04 pm
criszerriny wrote:how was 8x8x8 calculated?

Thanks
Do you mean WHY 8*8*8 is calculated?
Because if you visualize a cube with a painted surface, you'll have every cube on the top with a painted side and every cube on the bottom with a painted side=10-2=8
Same with the sides: you'll have every cube on each side with one painted side, so 10-2=8 for two opposite sides and 10-2=8 for other two opposite sides.
So, you'll get 8*8*8 cubes that are NOT painted at all.

10^2*6 cubes that have one painted side (100 cubes per surface times 6 sides of the cube)
The more you look, the more you see.
Join the discussion

by criszerriny » Mon May 04, 2009 1:29 pm
No, I meant How. I understand the reason, just didn't follow the method. Now , I do. Thanks.
Join the discussion