BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach Starts Oct 17
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Chris Peckover, 100th-Percentile GMAT Scorer

Oct 17 · Chris Peckover
Sat · 11:00 AM to 2:00 PM ET
Oct 20 · Chris Peckover
Tue, Thu · 8:00 to 10:00 PM ET
Oct 25 · Josh Braslow
Sun · 1:00 to 4:00 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemand 5 seats left Start anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

Proportion and chain rule

Expert replies
by maihuna » Sun May 03, 2009 7:38 am
A contract is to be completed in 46 days and 117 men were set to work, each working 8 hrs a day. After 33 days 4/7 of the work is completed. How many additional men may be employed so that the work may be completed in time, each men now working 9 hrs a day?

a.46
b.57
c.64
d.75
e.81
Last edited by maihuna on Sun May 03, 2009 10:41 am, edited 1 time in total.
Join the discussion
Source: — Problem Solving |

Re: Proportion and chain rule

by lilu » Sun May 03, 2009 10:36 am
maihuna wrote:A contract is to be completed in 46 days and 117 men were set to work, each working 8 hrs a day. After 33 days 4/7 of the work is completed. How many additional men may be employed so that the work may be completed in time, each men now working 8 hrs a day?

a.46
b.57
c.64
d.75
e.81
Are you sure the number of hours a day does not change for the 3/7 of the project that is left to be done?
The more you look, the more you see.
Join the discussion

by maihuna » Sun May 03, 2009 10:41 am
sorry met it is 9 hrs, edited the post
Join the discussion

Re: Proportion and chain rule

by lilu » Sun May 03, 2009 10:47 am
maihuna wrote:A contract is to be completed in 46 days and 117 men were set to work, each working 8 hrs a day. After 33 days 4/7 of the work is completed. How many additional men may be employed so that the work may be completed in time, each men now working 8 hrs a day?

a.46
b.57
c.64
d.75
e.81
i get 105 workers and that's not one of the options.
117men*8hrs*33days=4/7 of a job
30888hrs=4/7 of job
30888/ 4/7 = x hrs / 3/7
x=23166 hrs
#of workers*13 days*8hours=23166
#of workers=222.75~223
223-117=105..... and that's not one of the answer choices.... :roll:
The more you look, the more you see.
Join the discussion

by lilu » Sun May 03, 2009 10:49 am
OH!
That's what I thought!
Then--->
117men*8hrs*33days=4/7 of a job
30888hrs=4/7 of job
30888/ 4/7 = x hrs / 3/7
x=23166 hrs
#of workers*13 days*9hours=23166
# of workers=198
AND 198-117=81

I am not I'd be able to do this one in under two minutes b/c of all the calculations....
The more you look, the more you see.
Join the discussion

by dumb.doofus » Sun May 03, 2009 11:13 am
lilu wrote:OH!
That's what I thought!
Then--->
117men*8hrs*33days=4/7 of a job
30888hrs=4/7 of job
30888/ 4/7 = x hrs / 3/7
x=23166 hrs
#of workers*13 days*9hours=23166
# of workers=198
AND 198-117=81

I am not I'd be able to do this one in under two minutes b/c of all the calculations....
I think you can do it in two mins or less.. if you don't calculate so much.. so here is what I suggest:

Job done in 33 days by 117 men = 117*33*8 ------ (1)
This is 4/7 of the total job

Job done in 13 days by y men = y*13*9 --------- (2)
This is 3/7 of the total job..

So essentially the ratio of (1) and (2) should be equal to 4/3

i.e.

(117*33*8)/(y*13*9) = 4/3

13*9 = 117.. so that easily cancels out.. and actually its pretty simple calculation..

x = 198..

So extra men required = 81
One love, one blood, one life. You got to do what you should.
https://dreambigdreamhigh.blocked/
https://gmattoughies.blocked/
Join the discussion

by lilu » Sun May 03, 2009 11:41 am
Great approach,Smart.Guy!!! :D
The more you look, the more you see.
Join the discussion

by maihuna » Sun May 03, 2009 12:08 pm
dumb, its an question of setting up proportion, its too late here, i will soon post my version of ans..
Join the discussion

Re: Proportion and chain rule

by dtweah » Mon May 04, 2009 6:11 am
lilu wrote:
maihuna wrote:A contract is to be completed in 46 days and 117 men were set to work, each working 8 hrs a day. After 33 days 4/7 of the work is completed. How many additional men may be employed so that the work may be completed in time, each men now working 8 hrs a day?

a.46
b.57
c.64
d.75
e.81
i get 105 workers and that's not one of the options.
117men*8hrs*33days=4/7 of a job
30888hrs=4/7 of job
30888/ 4/7 = x hrs / 3/7
x=23166 hrs
#of workers*13 days*8hours=23166
#of workers=222.75~223
223-117=105.....

If abc is proportional to d, and efg is proportional to h we set up the proportion as follows. Find the proportionality constant k in the first proportion. Use in the second to solve for variable of interest.

abc=kd

k= abc/d.

In the problem if e is the number of men working then

Efg=k h

E= k x h/ f x g

E= ((117 x 8 x 33)/4/7 x 3/7 ) / 9 x 13.

E=198
198-117=81.

Warning: in problems involving big numbers, try to avoid multiplying the numbers. Leaving them as is can be helpful especially if you will have to break them up again.
Join the discussion