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Tricky root of a square

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Source: — Problem Solving |
Junior | Next Rank: 30 Posts
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by ornelaspedro » Sat May 02, 2009 8:52 am
If you square both terms you get (x+4)^2 = 9
Solve x^2 + 8x + 7 = 0
(x + 7) ( x + 1 ) = 0
x = - 7 x = - 1
Hence, x - 4 can be either -11 or -5
What's the correct answer?
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Junior | Next Rank: 30 Posts
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by keizer Soze » Sat May 02, 2009 9:05 am
The OA is -11
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