absolute value question

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Source: — Data Sufficiency |

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by maihuna » Mon Apr 13, 2009 8:32 am
do u mean lx-yl > lxl - lyl ?

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by smallsorrow » Mon Apr 13, 2009 9:15 am
yes, i do...

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by scoobydooby » Mon Apr 13, 2009 11:27 am
am getting B.

is lx-yl < lx-0l - ly-0l ?

1) y<x

case 1: let x and y both be positive.
-------0----y----x

we get lx-yl = lx-0l - ly-0l . No

case 2: let x be positive and y be negative.
-----y----0------x

we get lx-yl = lx-0l + ly-0l >lx-0l - ly-0l
=>lx-yl >lx-0l - ly-0l . Yes

not sufficient.


stmnt 2) xy<0
=> x and y are of opposite signs.

case 1: x>y
---y----0------x

we get lx-yl = lx-0l + ly-0l >|x|-|y|
=>lx-yl >lx-0l - ly-0l . Yes


case 2: x<y
---x----0-----y

we get lx-yl = lx-0l + ly-0l >|x|-|y|
=>lx-yl >lx-0l - ly-0l . Yes
sufficient.

hence, B

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by vittalgmat » Mon Apr 13, 2009 1:40 pm
B for me as well.

solved by plugging in numbers.

one takeaway from this.

whenever u see something like
xy < 0, immediately translate to the following
One of them is +ve and the other is -ve.
ie. x: +ve, y: -ve Or x: -ve, y: +ve

similarly
xy > 0
both x and y are +ve.