digits

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digits

by baller12q » Sun Mar 29, 2009 6:54 am
If N is a positive interger, is the Units digit of N equal to zero?

1) 14 and 35are factors of N

2) N= (2^5) (3^2) (5^7) (7^6)
Source: — Data Sufficiency |

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by scoobydooby » Sun Mar 29, 2009 7:12 am
Units digit of N equal to zero?

1) 14 and 35 are factors of N
=> 14=2*7, 35=7*5
if 14 and 35 are factors of N, then 2,5,7 are factors of N.
if 2 and 5 are both factors of N then 2*5*7*a*b*... will give the last digit as 0, as 2 *5 makes 10 and anything multiplied by 10 gives the last digit as 0
sufficient


2)N= (2^5) (3^2) (5^7) (7^6)
=> N= (2*5)^5*(3^2)*(7^6)*(5^2)
=> N=10^5 *(3^2)*(7^6)*(5^2)
will give the last digit as 0 as powers of 10 multiplied by any number will give 0 as the last digit
sufficient

hence D

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by baller12q » Sun Mar 29, 2009 9:32 am
i dont understand what you did in statement 2 cn you please help me clear that up

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by scoobydooby » Sun Mar 29, 2009 10:47 am
2)N= (2^5) (3^2) (5^7) (7^6)

in fact we need not do any groupings or rearranging. as long as we have a 2 and a 5 we get 10 and anything multiplied by 10 results in 0 as the unit digit. so statement 2 is sufficient