Very Simple solution:
(2^k)(5^(k-1))
This can be written as
(2^k)(5^k.5^-1)
As we can always write: M^a+b = (^a).(^b)
where (.) represents Multiplication
So (2^k)(5^k)/5
10^k/5
Now multiply numerator and dinominator both by 2
2[10^k/10]
2[10^k-1]
Answer A
Which of the following is equal to
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Slightly different approach:linfongyu wrote:Which of the following is equal to (2^k)(5^(k-1))?
A. 2(10^(k-1))
B. 5(10^(k-1))
C. 10^k
D. 2(10^k)
E. 10^(2k-1)
Please show your steps.
OA in a few...
2^k = (2^1) * (2^(k-1))
so:
(2^k)(5^(k-1))
= 2 * 2^(k-1) * 5^(k-1)
and since x^a * y^a = (x*y)^a,
= 2 * (2*5)^(k-1)
= 2 * 10^(k-1)

Stuart Kovinsky | Kaplan GMAT Faculty | Toronto
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