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puzzling diameter question

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Junior | Next Rank: 30 Posts
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by Kebab » Wed Mar 04, 2009 6:45 pm
area T = 2 area S

Diagonal and two sides make the right triangle with sides: 1:1: sqr.root2
radius T = sqr.root/2, radius S = 1/2
count the areas and u get the difference of 2
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Junior | Next Rank: 30 Posts
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Joined: Sun Jan 11, 2009 10:47 pm

Diameter

by NareshCS » Wed Mar 04, 2009 9:55 pm
Identify there are 3 figures Circle S, Circle T and a Square
Diameter of Circle S(d1) = side of Square
Diameter of Circle T(d2) = Diagonal of Square
Diagonal of Square = sqrt2* Side of Square
d2=sqrt(d1)
Area of Circle = (pi/4)*(diameter)^2
(Area of Circle S) =(pi/4)*(d1)^2
(Area of Circle P)= (pi/4)*(d2)^2
= (pi/4)*(sqrt 2*d1)^2
=(pi/4)*2*(d1)^2
=2*Area of Circle S
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