(x+3)^(2)+6(x+3)+9=0
(x+3)[(x+3)+6]=-9
(x+3)(x+9)=-9
x^2+12x+27=-9
x^2+12x+36=0
(x+6)^(2)=0
x+6=0
x=-6
Algebra
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truplayer256
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jhhatdaddy
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isnt it even easier than that?
(x^2+6x+9) + 6(x+3) + 9 = 0
x^2+6x+9+6x+18+9=0
x^2+12x+36-0
(x+6)^2=0
(x^2+6x+9) + 6(x+3) + 9 = 0
x^2+6x+9+6x+18+9=0
x^2+12x+36-0
(x+6)^2=0
2 ways
either develop as and solve
or recognize that X^2 +6X+9 is (X+3)^2
and factorize x+3 and then solve
and refactorize x+6 Recognizing that X^2 +12X+36
is (X+6 ) ^2
ps it is the formula (a+b)^2 = a^2 +b^2+2ab
hope it helps
either develop as and solve
or recognize that X^2 +6X+9 is (X+3)^2
and factorize x+3 and then solve
and refactorize x+6 Recognizing that X^2 +12X+36
is (X+6 ) ^2
ps it is the formula (a+b)^2 = a^2 +b^2+2ab
hope it helps
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