BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach Starts Oct 17
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Chris Peckover, 100th-Percentile GMAT Scorer

Oct 17 · Chris Peckover
Sat · 11:00 AM to 2:00 PM ET
Oct 20 · Chris Peckover
Tue, Thu · 8:00 to 10:00 PM ET
Oct 25 · Josh Braslow
Sun · 1:00 to 4:00 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemand 5 seats left Start anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

How to solve this question

Expert replies
by 4neg » Thu Jan 29, 2009 8:53 am
In a certain department store, which has four sizes of a specific shirt, there are 1/3 as many small shirts as medium shirts, and 1/2 as many large shirts as small shirts. If there are as many x-large shirts as large shirts, what percent of the shirts in the store are medium?
Join the discussion
Source: — Problem Solving |

by DanaJ » Thu Jan 29, 2009 9:16 am
1/3*m = s
1/2*l = s = 1/3*m, so this means that l = 2/3*m
l = xl = 2/3*m.
s + m + l + xl = Total, so 1/3*m+m+2/3*m+2/3*m = T or 8/3*m = total. This means that m = 3/8*T = 0,375*t = 37,5%*T.
Join the discussion

by masuarezdl » Thu Jan 29, 2009 10:17 am
Wouldnt the second equation be "(1/2)S = L"?
Join the discussion

by r_walid » Thu Jan 29, 2009 10:33 am
Dana, I agree with your procedure except that I think L = 1/2S

this means that the total = S+M+L+X = 1/3M + M+ 2*L (since L=X)
so The total = 5/3M

The question asks about the percentage of M from the total, so it's M/T = 3/5 or 60%
Join the discussion

by DanaJ » Thu Jan 29, 2009 10:43 am
I don't really know what to say... Can you please provide OA?>
Join the discussion

by BuckeyeT » Thu Jan 29, 2009 11:13 am
First post, so please forgive me if I'm misreading, but r_walid's calculation looks correct.

Same calculation process. Solve all for m. Know s+m+l+xl=100%
Total 5/3m=100%, so 3/5*100=60%.
Join the discussion

by dimonya » Sun Feb 01, 2009 12:51 pm
In a certain department store, which has four sizes of a specific shirt, there are 1/3 as many small shirts as medium shirts, and 1/2 as many large shirts as small shirts. If there are as many x-large shirts as large shirts, what percent of the shirts in the store are medium?

Easiest way is to bring everything to common units and regress everythinh through them .. So we have ..

S,M,L,XL
S=M/3
M=M
L= 1/2S=1/2(M/3)= M/6
XL= M/6

So all shirts are S+M+L+XL =M/3+M+2(M/6)=5M/3

Percentage of M is just M/all shirts = M/(5M/3) = 3/5

The hardest part is the wording .. i.e is it S=M/3 or S=3M ..
Join the discussion

by chiller » Mon Feb 02, 2009 4:49 am
For this question, I used the "plug in" method.

Knowns:
S = 1/3M
S= 1/2L
XL=L

Question:
M=?

Since I saw 1/3 and 1/2 in the fractions, I decided to pick a number to start out with that is divisible by both. I chose 60.

Let's say there are L=60.

From that,

XL=60
L=60
S=1/2L=1/2(60)=30

From the small, we also know that S=1/3M, therefore:

30 = 1/3M
M = 90.

The total of all the shirts together = 240.
So, the question is, what percentage of 240 is 90?

90/x = 240/100

Hence,
x=37.5%

Hope this helps.
Join the discussion

Resolve

by nattatob » Mon Feb 02, 2009 8:26 am
There are four sizes in that department; S, M, L and XL .

(1/3)(M) = S
(1/2)(S) = L
XL = L

S +M+ L + XL
(1/3)(M)+M+(1/2)(1/3)(M)+(1/2)(1/3)(M)

= M/3+3M/3+M/6+M/6
= 10M/6 = Total

M/Total = 6/10 = 60%
Attachments
1untitled6.jpg
Join the discussion

by coffee5251 » Mon Feb 02, 2009 10:47 am
I also go 60%. What is the OA?
Join the discussion

Re: Resolve

by gabriel » Tue Feb 03, 2009 6:55 pm
nattatob wrote:There are four sizes in that department; S, M, L and XL .

(1/3)(M) = S
(1/2)(S) = L
XL = L

S +M+ L + XL
(1/3)(M)+M+(1/2)(1/3)(M)+(1/2)(1/3)(M)

= M/3+3M/3+M/6+M/6
= 10M/6 = Total

M/Total = 6/10 = 60%


Lol cute kid, but is there a point behind posting the picture.
Join the discussion

Re: Resolve

by mrsmarthi » Tue Feb 03, 2009 8:08 pm
I can see some weird formula on the kid's dress. Probably might want to convey - "BORN MATHEMATICIAN".

Hey BTW, kid is really cute. Now coming back to the solution, my approach is slightly different.

Given M be the count of Medium shirts.

1/ 3 Small = Medium ==> Small = 3M
Medium = M
1/2 Large = Small ==> Large = 2 Small = 6M
XL = L ==> Xl = 6M

% of Medium shirts = M / (3M + M + 6M +6M) * 100 =
==> 1/16 * 100 = 6 1/4

And my ans is - 6 1/4.
Join the discussion