BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach Starts Oct 17
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Chris Peckover, 100th-Percentile GMAT Scorer

Oct 17 · Chris Peckover
Sat · 11:00 AM to 2:00 PM ET
Oct 20 · Chris Peckover
Tue, Thu · 8:00 to 10:00 PM ET
Oct 25 · Josh Braslow
Sun · 1:00 to 4:00 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemand 5 seats left Start anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions
Start free 5-day trial
Read 559 reviewsTarget Test Prep

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

Norman window

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
Master | Next Rank: 500 Posts
Posts: 132
Joined: Tue Oct 07, 2008 4:59 pm
Thanked: 4 times
by vladmire » Mon Jan 19, 2009 9:20 am
A norman window consists of a retangle surmounted by a semicircle. Find the area of the norman window. How much wood fram is needed to enclose the window?

L-6
W-4

I got the rectangle part of the proble...
A=LW
A=6*4=24
24+2Pi=30.28

How do I get the semicircle?
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Source: — Problem Solving |
User avatar
Legendary Member
Posts: 2134
Joined: Mon Oct 20, 2008 11:26 pmFollowed by: 25 members
Thanked: 237 times
GMAT Score:730

by logitech » Mon Jan 19, 2009 9:32 am
This should help
Attachments
cemi.jpg
LGTCH
---------------------
"DON'T LET ANYONE STEAL YOUR DREAM!"
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Senior | Next Rank: 100 Posts
Posts: 35
Joined: Wed Oct 29, 2008 5:14 am

Re: Norman window

by coffee5251 » Thu Jan 29, 2009 5:26 pm
vladmire wrote:A norman window consists of a retangle surmounted by a semicircle. Find the area of the norman window. How much wood fram is needed to enclose the window?

L-6
W-4

I got the rectangle part of the proble...
A=LW
A=6*4=24
24+2Pi=30.28

How do I get the semicircle?
Why do you add 2Pi to the area? How do you know what the radius of semicrircle is?

Also can you explain why you would find the hypotenuse of the triangle? How is that related to the window frame?
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Legendary Member
Posts: 727
Joined: Sun Jun 08, 2008 9:32 pmFollowed by: 1 member
Thanked: 8 times

by umaa » Thu Jan 29, 2009 6:55 pm
A rectangle SURMOUNTED by a semi circle. So, the semicircle is on top of the rectangle.

Area of norman window is, Area of rec + Area of S.circle.

Area of S. circle is, (pi * r^2)/2; r = l/2 = 6/2 = 3

= 6*4 + pi * 9/2

Total area = = 24 + 4.5pi


To find the wood frame needed to enclose the window is to add rectangle's perimeter and the length of the arc.

= peri. of rec + length of arc
= 2 (6+4) + 2*pi*3/2
= 20 + 3*pi

Guys, let me know the OA.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Master | Next Rank: 500 Posts
Posts: 221
Joined: Wed Jan 21, 2009 10:33 amFollowed by: 1 member
Thanked: 12 times

by krisraam » Thu Jan 29, 2009 8:27 pm
I think this is ambiguous.

Answer is either 20 + 3pi or 20 + 2Pi depending on where the semi circle is surmounted. If the semicircle over the length its 20+3pi. if its over the width its 20+ 2Pi.

Thanks
Raama
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1