Value of X

[cartera]

(X^2+2x-8)/x^2-6x+8=?

A.1
B.-1
C.x/3
D.x+4/x-4
E.x+8-x-8



Im getting: (x+2)(x-4)/(x+5)(x+1)

How can I proceed

[DanaJ]

You are getting it a bit wrong. The correct form would be:

(x+4)(x-2)/(x-4)(x-2), giving you (x+4)/(x-4)


Answer D.

[gaggleofgirls]

Both your numerator and your denominator are a bit off:

Numerator = x^2 +2X -8, so you need (x - #) (X + #) where the #s are 2 apart, multiply to 8 and the larger # is + (so that you get +2x, not -2x). Those numbers are 2 and 4 such that the equation is (x - 2)(x + 4)

Denominator = x^2 - 6X + 8, so now you need (x - #)(x - #) (in order to get + # at the end) and you need numbers that are 2 apart and multiply to 8, so again you have 2 and 4 so that the equation is (x - 2) (x - 4)

(x - 2) (x + 4) / (x - 2)(x - 4) you can cancel out the (x-2) in both the numerator and the denominator and that leaves you with answer D.

-Carrie

[krisraam]

IT IS D

[aroon7]

yes it is D

[johnybravo]

its D