Square root

[ajmoney09]

P^2 = (Q^4)(R^6)

I had a problem like this, the solution said to take the "positive square root of this" which in turn would give me P= (Q^2)(R^3)

Why does Rs exponent go down to 3? why not 4?

[mrsmarthi]

Taking the positive square root means, dividing the exponent by 2.

p ^ 2 = (q ^ 4) (r ^ 6)

Taking the sqrt on both side, it is

p ^ (2 / 2) = (q ^ (4/2)) (r ^ (6/2))

==> p = (q ^ 2) (r ^ 3).

Hope you got it.

[ajmoney09]

Taking the positive square root means, dividing the exponent by 2.

p ^ 2 = (q ^ 4) (r ^ 6)

Taking the sqrt on both side, it is

p ^ (2 / 2) = (q ^ (4/2)) (r ^ (6/2))

==> p = (q ^ 2) (r ^ 3).

Hope you got it.

Thanks, that was simple enough....

if i was taking the cube root, would i divide by 3?

[aroon7]

if i was taking the cube root, would i divide by 3?

You are right ajmoney...