manhatan gmat 3

[resilient]

If n is a non-negative integer such that 12n is a divisor of 3,176,793, what is the value of n12 – 12n ?


a.- 11
b.- 1
c.0
d.1
e.11

qa is b i chose D

[stellategang]

If n is a non-negative integer such that 12n is a divisor of 3,176,793, what is the value of n12 – 12n ?


a.- 11
b.- 1
c.0
d.1
e.11

qa is b i chose D

something is wrong with your question

n*12 - 12*n = 0

[resilient]

If n is a non-negative integer such that 12n is a divisor of 3,176,793, what is the value of n^12 – 12^n ?


a.- 11
b.- 1
c.0
d.1
e.11

qa is b i chose D

[cris]

Engin this is a really tricky question.

What you have to find oout first is that n=0

So: 0^12=0 ; 12^0=1

So: 0-1= -1 ......B is the correct answer

You get it?

[dragonheart]

well dear

i am not getting the qns. since 12n is divisor of x and x isnot a multiple of zero how come we get the value of n = 0.

also is it 12n, 12^n, 12*n.
with no offence, plz do not post such ambigous qns.

thanx

[resilient]

the question hangs on the understanding of the multipilicity of that number. since the 3176793 ends in 3 the 12n must be compatible but i dont understand hwo n = 0?


tricky questions

[Stuart@KaplanGMAT]

Sorry, this question makes no sense at all.

If n is an integer (positive, negative or 0), there's no value of n that will make 12n a divisor (i.e. factor) of an odd number.

0 is a multiple of every number, it's a divisor of no numbers.

[xilef]

Wouldn't the only possible value for 12n be 1, in which case n=1/12 :

(1/12)^12-12^(1/12)=-1

[Stuart@KaplanGMAT]

Wouldn't the only possible value for 12n be 1, in which case n=1/12 :

(1/12)^12-12^(1/12)=-1

Except that the question says:

"If n is a non-negative integer"

which is why there's no possible value for n that satisfies the requirement:

12n is a divisor of 3,176,793.

[Edthesock]

I want to point out that the question is NOT 12n and n12 - 12n, it is the following:

If n is a non-negative integer such that 12^n is a divisor of 3,176,793, what is the value of n^12 - 12^n.

12^0 = 1, and one is a divisor of all numbers (possibly with some exception I'm not thinking of, like 0 or infinity or something).

n^12 - 12^n = 0 - 1 = -1 so B is our answer

I wish people would post correctly, stuff like this just frustrates everyone.