crazy coordinates

[maihuna]

In the rectangular coordinate system, are the points (a, b) and (c, d) equidistant from the origin?

(1) a/b = c/d

(2) (a^2)^1/2 + (b^2)^1/2 = (c^2)^1/2 + (d^2)^1/2

[DanaJ]

Could you please check if you've written statement 2 correctly? I would expect smth like [a^2+b^2]^1/2 = [c^2+d^2]^1/2

[hypik21]

IMO b, if the equation is stated correctly, it infers that A,B,C,D can be negative but they will have the same absolute values. It cant be A because if a was 1 and b was 2, C could be 4, D could be 8, insufficient

[logitech]

In other words IS a^2+b^2=c^2+d^2 ?

(1) a/b = c/d

1/2 = 2/4

Insuf

(2) (a^2)^1/2 + (b^2)^1/2 = (c^2)^1/2 + (d^2)^1/2

Absolute a + b = Absolute c + d

1+4 = 2+3

INSUF

together

We know they are proportional and theirs ABS are the same

So A/B=C/D=1

SUF

I would go with C

[maihuna]

You rock sir. Its C.

[maihuna]

Could you please check if you've written statement 2 correctly? I would expect smth like [a^2+b^2]^1/2 = [c^2+d^2]^1/2

See Logitech boss has answered it.