dnkcdnguy wrote:Can someone show me the best way to solve the following question:
2+2+2^2+2^3+2^4+2^5+2^6+2^7+2^8=
A) 2^9
B) 2^10
C) 2^16
D) 2^35
E) 2^37
Answer: A
Thanks
2+2[1+2+2^2+2^3+2^4+2^5+2^6+2^7]
figure in bracket is a GP series , a =1 , r = 2 , n = 7
sum of series , a(r^n+1-1)/r-1
2+2[1(2^8-1)/2-1]
2+2(2^8-1)
2+2^9-2
2^9












