BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach Starts Oct 17
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Chris Peckover, 100th-Percentile GMAT Scorer

Oct 17 · Chris Peckover
Sat · 11:00 AM to 2:00 PM ET
Oct 20 · Chris Peckover
Tue, Thu · 8:00 to 10:00 PM ET
Oct 25 · Josh Braslow
Sun · 1:00 to 4:00 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemand 5 seats left Start anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

percent

Expert replies
by [email protected] » Sat Dec 27, 2008 10:33 am
14. Mr. Kramer, the losing candidate in a two-candidate election, received 942,568 votes, which was exactly 40 percent of all the votes cast. Approximately what percent of the remaining votes would he need to have received in order to have won at least 50 percent of all the votes cast?
(A) 10%
(B) 12%
(C) 15%
(D) 17%
(E) 20%

D

is there an easy way to do this problem? [/spoiler]
Join the discussion
Source: — Problem Solving |

by acecoolan » Sat Dec 27, 2008 11:11 am
The fastest way I could think of is Approximation

942,568 ...approx => 950,000 = 40% of Total

Again I prefer scaling down the numbers so rather than 950,000, just work with 950f

950 = 40% of X -> X = 2375 ...approx 2400

Hence 50% of X = 1200
To get to 50%, candidate requires 1200 - 950 = 250

So 250 is what % of remaining votes (remaining votes = 2400 - 950)

250/1450 * 100 = 17% approx

Hence D)

Hope this helps.

-A
Join the discussion

Re: percent

by Ian Stewart » Sat Dec 27, 2008 11:40 am
[email protected] wrote:14. Mr. Kramer, the losing candidate in a two-candidate election, received 942,568 votes, which was exactly 40 percent of all the votes cast. Approximately what percent of the remaining votes would he need to have received in order to have won at least 50 percent of all the votes cast?
(A) 10%
(B) 12%
(C) 15%
(D) 17%
(E) 20%

D

is there an easy way to do this problem? [/spoiler]
The number 942,568 is irrelevant to the problem. 60% of people didn't vote for Kramer; Kramer needed to get 1 out of 6 of these people to vote for him to reach 50% of all the votes. 1/6 ~ 17%.
For online GMAT math tutoring, or to buy my higher-level Quant books and problem sets, contact me at ianstewartgmat at gmail.com

ianstewartgmat.com
Join the discussion

Re: percent

by acecoolan » Sat Dec 27, 2008 6:23 pm
Ian Stewart wrote:
The number 942,568 is irrelevant to the problem. 60% of people didn't vote for Kramer; Kramer needed to get 1 out of 6 of these people to vote for him to reach 50% of all the votes. 1/6 ~ 17%.
Wow ...thanks Ian.
Join the discussion

Re: percent

by vittalgmat » Sat Dec 27, 2008 11:54 pm
Ian Stewart wrote:
[email protected] wrote:14. Mr. Kramer, the losing candidate in a two-candidate election, received 942,568 votes, which was exactly 40 percent of all the votes cast. Approximately what percent of the remaining votes would he need to have received in order to have won at least 50 percent of all the votes cast?
(A) 10%
(B) 12%
(C) 15%
(D) 17%
(E) 20%

D

is there an easy way to do this problem? [/spoiler]
The number 942,568 is irrelevant to the problem. 60% of people didn't vote for Kramer; Kramer needed to get 1 out of 6 of these people to vote for him to reach 50% of all the votes. 1/6 ~ 17%.
This is surely a WOW!!! I never saw it this way..
thanks Ian.
Join the discussion