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SQ RT

by sogmat » Thu Dec 18, 2008 7:46 pm
If x < 0, then &#8730;(-x&#9474;x&#9474;) is

A. -x
B. -1
C. 1
D. x
E. &#8730;x
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by EmilKhalikov » Thu Dec 18, 2008 8:32 pm
x<0 => -x > 0 & |x| > 0 => -x * |x| > 0 => Taking square root is possible.

The answer is either A or D (do not forget, &#8730;4 is -2 and 2). My intuition tells me that they are looking for positive answers, hence it is A (x<0 => -x>0)
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by brb588 » Thu Dec 18, 2008 9:19 pm
I'm sorry, but I have no idea how you arrived at your answer. This question seems very suspect...
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by vishubn » Thu Dec 18, 2008 9:22 pm
x < 0, then &#8730;(-x&#9474;x&#9474;) is

First of all x <0 so it is -ve thru out....

one more rule to remember there is no value alled sqr root of a negative number...

|x| is + ve for any values

x=-ve

-(-x)*x=x^2

sqrt rt of x^2 = =/- x

but we know x <0 answer is -x

OA A

Vishu
KILL !! DIE !! or BEAT my FEAR !!! de@D END!!
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