B
from the stem, we know that both m*v and p*v are negative, which means that one of the terms in each combo is negative. so we have to find which term is negative.
1) v doesn't necessarily have to be positive. say m = 5 and p = 6, so v can be any number in this case. on the other hand, say v = 1, and m = -6, p = -5.
INSUFFICIENT
2) if m is negative, then v has to be positive to make m*v negative.
SUFFICIENT.
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From GMAT Prep
Source: Beat The GMAT — Data Sufficiency |
mv<pv<0 implies mv-pv<0, i.e. v(m-p)<0CIAO1982 wrote:If m*v < p*v < 0 , is it v > 0 ?
1) m < p
2) m < 0
This is possible when either
v<0 and (m-p)>0, i.e. m>p
or, v>0 and (m-p)<0, i.e., m<p
Stm 1: m<p, so v>0 suff
Stm2: m<0...tells us nothing about p, hence in suff
Answer is A
mv<pv<0 is the stem !....
it is also true
pv<0
and pv>mv or p>m
A) it stating the same thign as stem ! no info on v, we know pv<0 but not p or v !!
Insuff
B)m<0 !! m is -ve !!
m * v !, v has to positive !!
if not mv will never be < 0
IMO B
it is also true
pv<0
and pv>mv or p>m
A) it stating the same thign as stem ! no info on v, we know pv<0 but not p or v !!
Insuff
B)m<0 !! m is -ve !!
m * v !, v has to positive !!
if not mv will never be < 0
IMO B
KILL !! DIE !! or BEAT my FEAR !!! de@D END!!
I am not sure if we can say pv>mv or p>m because we do not know if v is +ve or -ve, but we can definitely say pv-mv>0...my two centsvishubn wrote:mv<pv<0 is the stem !....
it is also true
pv<0
and pv>mv or p>m
A) it stating the same thign as stem ! no info on v, we know pv<0 but not p or v !!
Insuff
B)m<0 !! m is -ve !!
m * v !, v has to positive !!
if not mv will never be < 0
IMO B
It's D : From the stem we know mv<pv<0
Which means : V can be negative or positive depending on M and P
If M is positive V is negative => P is positive and for the stem to be true m<p
If m is negative v is positive and P is negative but for the stem to be true m>p.
Now from 1: m<p => v < 0 Sufficient
From 2 : m<0 => p<0, m>p and v > 0 : Sufficient
- pradeep
Which means : V can be negative or positive depending on M and P
If M is positive V is negative => P is positive and for the stem to be true m<p
If m is negative v is positive and P is negative but for the stem to be true m>p.
Now from 1: m<p => v < 0 Sufficient
From 2 : m<0 => p<0, m>p and v > 0 : Sufficient
- pradeep
In the land of night, the chariot of the sun is drawn by the grateful dead
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GMATPREP1 - 550 (Oct 08)
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Good solutions All!
I would also like to share Ian's approach for Stmt I
mv < pv
m<p
Multiply both sides by v.If v was negative then it would make mv>pv since the inequality reverseS when u multiply by a negative number but its given mv<pv so v has to be positive.
SUFF
I would also like to share Ian's approach for Stmt I
mv < pv
m<p
Multiply both sides by v.If v was negative then it would make mv>pv since the inequality reverseS when u multiply by a negative number but its given mv<pv so v has to be positive.
SUFF
Hey Bro !pbanavara wrote:It's D : From the stem we know mv<pv<0
Which means : V can be negative or positive depending on M and P
If M is positive V is negative => P is positive and for the stem to be true m<p
If m is negative v is positive and P is negative but for the stem to be true m>p.
Now from 1: m<p => v < 0 Sufficient
From 2 : m<0 => p<0, m>p and v > 0 : Sufficient
- pradeep
I liked ur conversation with ur penguin
vishu
KILL !! DIE !! or BEAT my FEAR !!! de@D END!!
